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Monday, December 6, 2010

a3+b3 = (a+b) (a2-ab+b2)

a3-b3 = (a-b) (a2+ab+b2)

(a+b)3 = a3+b3+3ab(a+b)

(a-b)3 = a3-b3-3ab(a-b)

(a+b+c) (a2+b2+c2-ab-bc-ac) = a3+b3+c3-3abc

Phew kay. needed to make sure I remember that. Hope it stays there till morning. And those are just the cube deduction formulas. -_-

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