a3+b3 = (a+b) (a2-ab+b2)
a3-b3 = (a-b) (a2+ab+b2)
(a+b)3 = a3+b3+3ab(a+b)
(a-b)3 = a3-b3-3ab(a-b)
(a+b+c) (a2+b2+c2-ab-bc-ac) = a3+b3+c3-3abc
Phew kay. needed to make sure I remember that. Hope it stays there till morning. And those are just the cube deduction formulas. -_-
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